floor
Returns the largest integer not greater than x
Syntax
floor(x) (init-, control-, or audio-rate arg allowed)
floor(k/i[]) (k- or i-arrays )
where the argument within the parentheses may be an expression. Value converters perform arithmetic translation from units of one kind to units of another. The result can then be a term in a further expression.
Examples
Here is an example of the floor opcode. It uses the file floor.csd.
Example of the floor opcode. |
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| <CsoundSynthesizer>
<CsOptions>
; Select audio/midi flags here according to platform
-odac ;;;realtime audio out
;-iadc ;;;uncomment -iadc if realtime audio input is needed too
; For Non-realtime ouput leave only the line below:
;-o floor.wav -W ;;; for file output any platform
</CsOptions>
<CsInstruments>
sr = 44100
ksmps = 32
nchnls = 2
0dbfs = 1
instr 1
idiv init 1
loop:
inumber = 9
i1 = inumber / idiv
ifl = floor(i1)
print inumber, idiv, ifl ;print number / idiv = result using floor
idiv = idiv + 1
if (idiv <= 10) igoto loop
endin
</CsInstruments>
<CsScore>
i 1 0 0
e
</CsScore>
</CsoundSynthesizer>
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The output should include lines like these:
instr 1: inumber = 9.000 idiv = 1.000 ifl = 9.000
instr 1: inumber = 9.000 idiv = 2.000 ifl = 4.000
instr 1: inumber = 9.000 idiv = 3.000 ifl = 3.000
instr 1: inumber = 9.000 idiv = 4.000 ifl = 2.000
instr 1: inumber = 9.000 idiv = 5.000 ifl = 1.000
instr 1: inumber = 9.000 idiv = 6.000 ifl = 1.000
instr 1: inumber = 9.000 idiv = 7.000 ifl = 1.000
instr 1: inumber = 9.000 idiv = 8.000 ifl = 1.000
instr 1: inumber = 9.000 idiv = 9.000 ifl = 1.000
instr 1: inumber = 9.000 idiv = 10.000 ifl = 0.000
Here is another example of the floor opcode. It uses the file floor2.csd.
| <CsoundSynthesizer>
<CsOptions>
; Select audio/midi flags here according to platform
-odac ;;;RT audio out
;-iadc ;;;uncomment -iadc if RT audio input is needed too
; For Non-realtime ouput leave only the line below:
; -o floor.wav -W ;;; for file output any platform
; By Stefano Cucchi 2024
</CsOptions>
<CsInstruments>
sr = 44100
ksmps = 32
0dbfs = 1
nchnls = 2
instr 1
gkrandom randomh 1, 45, 300, 2, 3 ; generate some random numbers
gkrandomFLOOR = floor (gkrandom) ; take the integer part
gkrandomFRAC = frac (gkrandom) ; take the fractional part
endin
instr 10
ktrigger metro 4
kmintim = 0
kmaxnum = 10
kinsnum = 20
kwhen = 0
kdur = ktrigger*0.25
schedkwhen ktrigger, kmintim, kmaxnum, kinsnum, kwhen, kdur
endin
instr 20
irandomFLOOR = i(gkrandomFLOOR)
irandomFRAC = i(gkrandomFRAC)
; Use the integer part to control the number of harmonics of every note
; after converting (k) value to (i)
prints "generated value = %f\n", i(gkrandom)
prints "--> floor value = %d\n", irandomFLOOR
a1 buzz 0.5, 120, irandomFLOOR, 1
kenvelope linseg 0, p3*0.1, 1, p3*0.8, 1, p3*0.1, 0
a1 = a1*kenvelope
aL, aR pan2 a1, irandomFRAC, 1 ; use the fractional part to control the pan position
outs aL, aR
endin
</CsInstruments>
<CsScore>
f 1 0 16384 10 1
i 1 0 10
i 10 0 10
e
</CsScore>
</CsoundSynthesizer>
|
Here is an example for the rounding-group, comparing the different rounding opcodes. It uses the file rounding-group.csd.
Example of the rounding group. |
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| <CsoundSynthesizer>
<CsOptions>
-odac ;
</CsOptions>
<CsInstruments>
sr = 44100
ksmps = 32
; by tgrey 2020
instr 1
iLoopStart = p4
iLoopEnd = p5
iOffset = p6
iCount init iLoopStart
if(iLoopStart<iLoopEnd) then ; loop going up
while iCount <= iLoopEnd do
iVal = iCount+iOffset
iRound = round(iVal)
iInt = int(iVal)
iFloor = floor(iVal)
iCeil = ceil(iVal)
print iVal, iRound, iInt, iFloor, iCeil
iCount = iCount + 1
od
elseif(iLoopEnd<iLoopStart) then ; loop going down
while iCount >= iLoopEnd do
iVal = iCount+iOffset
iRound = round(iVal)
iInt = int(iVal)
iFloor = floor(iVal)
iCeil = ceil(iVal)
print iVal, iRound, iInt, iFloor, iCeil
iCount = iCount - 1
od
endif
endin
</CsInstruments>
<CsScore>
i1 0 .1 0 10 .5
i1 .2 .1 0 -10 .5
e
</CsScore>
</CsoundSynthesizer>
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See also
Mathematical Functions
Credits
Author: Istvan Varga
New in Csound 5
2005